Just wondering if it is possible to set the number of nodes in a layer for
fluid.mlpregressor~? The docs mention that it defaults to 2 layers and 3 nodes/layer. It’s clear that one can set the number of layers with
@hidden, but how to set the nodes?
@hidden takes a list, so you input however many layers you want, and the number per entry in the list is the amount of nodes per layer.
the in and out are set by your input and output size, but yes, hidden is a list of your hidden layers structures. they share the same activation, except the output one which has its own attribute
I see. So if I have
@hidden 3 64 will I get 3 hidden layers with 64 nodes each?
Nope. Syntax is a bit confusing…
If you want three hidden layers with 64 nodes each it would be
@hidden 64 64 64. In other places the general syntax is [number] -> [modifier] (e.g.
@addrange 2 4 = start at column 2 and add 4 columns after that), but here it’s completely separate numbers denoting the amount of nodes per layer.
As an aside, I’m guessing this is another scikit syntax import, but something like
@hiddenlayers or something like that may make more sense in terms of legibility as the singular of
@hidden makes it unclear that it takes a list (like
@fftsettingSSS), and also makes it seem like it’s referring to something else, like a binary flag or something.
OK! Yes, +1 for naming it
@hiddenlayers to suggest it is a list. It is also very good that you can set the sizes per layer! In tensorflow/keras I usually see that the first hidden layer is the biggest, and then it feeds forward to gradually smaller layers something like
@hidden 128 64 32 (or maybe 64 64 32 16, depends on the speed and the complexity/nature of the task…).